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[백준] 11722번 : 가장 긴 감소하는 부분 수열 with python3, cpp

25 Aug 2018

Reading time ~1 minute

https://www.acmicpc.net/problem/11722


n = int(input())
d = list(map(int, input().split()))
d.insert(0,0)
sequence = [1]*(n+1)
# sequence[i]는 i를 포함한 감소하는 수열중 가장 긴 수열

for i in range(n+1):
    for j in range(i):
        if d[j] > d[i] and sequence[i] < sequence[j]+1:
            sequence[i] = sequence[j]+1
print(max(sequence))

n = int(input())
d = list(map(int, input().split()))
sequence = [1]*(n+1)
sequence[0]=0
# 0일 때도 신경써야 한다

for i in range(n+1):
    for j in range(i):
        if d[j] > d[i] and sequence[i] < sequence[j]+1:
            sequence[i] = sequence[j]+1
print(max(sequence))

#include <iostream>
#include <algorithm>
#include <vector>
using namespace std;
int main() {
    int n;
    cin >> n;
    vector<int> a(n);
    for (int i=0; i<n; i++) {
        cin >> a[i];
    }
    vector<int> d(n);
    for (int i=0; i<n; i++) {
        d[i] = 1;
        for (int j=0; j<i; j++) {
            if (a[j] > a[i] && d[j]+1 > d[i]) {
                d[i] = d[j]+1;
            }
        }
    }
    cout << *max_element(d.begin(),d.end()) << '\n';
    return 0;
}



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