[백준] 10989번 : 수 정렬하기 3 with python3

import sys
read = lambda : sys.stdin.readline().strip()
write = lambda x: sys.stdout.write(str(x)+ "\n")

m=10001
a=[0]*m

for _ in range(int(read())):
    a[int(read())]+=1

for j in range(10001):
    for _ in range(a[j]):
        write(j)